Question

Find the length the wooden strip required to frame a photograph whose length and breadth are
6.2 m and 5.9 cm respectively.
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Answer 1

Correct Question:-

• Find the length the wooden strip required to frame a photograph whose length and breadth are 6.2 m and 5.9 m respectively.

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Given:-

• Length of the photograph is 6.2 m.
• Breadth of the photograph is 5.9 m.

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To find:-

• The length of the wooden strip.

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Solution:-

Here,

• Length = 6.2 m
• Breadth = 5.9 m

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★Formula used:-

${\dag}\:{\underline{\boxed{\sf{\purple{Perimeter\: of\: rectangle = 2(length + breadth}}}}}$

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$\tt\longrightarrow\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: {2(l + b)}$

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$\tt\longrightarrow\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: {2(6.2 + 5.9)}$

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$\tt\longrightarrow\: \: \: \: \: \: \: \: \: \: \: \: {2(12.1)}$

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$\sf\longrightarrow\: \: \: \: \: \: \: \: {\boxed{\red{24.2\: m}}}$

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Hence,

• the length of the wooden strip is 24.2 m.

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★More to know :-

$\sf{Area\;of\;Rectangle\;=\;Length\;\times\;Breadth}$

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$\sf{Area\;of\;Square\;=\;(Side)^{2}}$

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$\sf{Area\;of\;Triangle\;=\;\dfrac{1}{2}\;\times\;Base\;\times\;Height}$

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$\sf{Area\;of\;Parallelogram\;=\;Base\;\times\;Height}$

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$\sf{Area\;of\;Circle\;=\;\pi r^{2}}$

$\sf{Perimeter\;of\;Rectangle\;=\;2\;\times\;(Length\;+\;Breadth)}$

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$\sf{Perimeter\;of\;Rectangle\;=\;4\;\times\;(Side)}$

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$\sf{Perimeter\;of\;Circle\;=\;2\pi r}$

Answer 2

Question:

Find the length the wooden strip required to frame a photograph whose length and breadth are 6.2 m and 5.9 m respectively.

Given :

• Length = 6.2 m
• Breadth = 5.9 m

To find :

• The length of wooden strip required to frame a photograph

Solution :

To find the length of wooden strip required, we need to find the perimeter of the photograph whose dimensions are 6.2 m and 5.9 respectively.

Perimeter of the rectangle = 2( l + b)

:➠ 2 ( 6.2 + 5.9 )

:➠ 2 (12.1)

:➠ 24.2

Hence, the length of wooden strip required = 24.2 cm