Math, asked by anjali1387, 4 months ago

find the length x+4 and breadth 2x+2 of the rectangle if the perimeter is 78 meter​

Answers

Answered by MS5758
0
P=2(l+b)
78=2[(x+4)+(2x+2)]
78=2(3x+6)
78=6x+12
78-12=6x
66=6x
X=66/6
X=11
Answered by ASHCAD
0

Answer:

Length = 15 m

Breadth = 24m

Step-by-step explanation:

Given,

Length ( L ) = x + 4

Breadth ( B ) = 2x + 2

Perimeter of Rectangle = 2(L + B) = 78 m

Now,

Since Perimeter

= 2(L + B) = 78

=> 2(x + 4 + 2x +2) = 78

=> 2(3x + 6) = 78

=> 2 × 3(x + 2) = 78

=> 6(x + 2) = 78

=> x + 2 = 78/6

=> x + 2 = 13

=> x = 13 - 2

=> x = 11

Since x = 11

Length ( L ) = x + 4 = 11 + 4 = 15 m

Breadth ( B ) = 2x + 2 = 2(11) + 2 = 22 + 2 = 24 m

Hope it helps

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