find the length x+4 and breadth 2x+2 of the rectangle if the perimeter is 78 meter
Answers
Answered by
0
P=2(l+b)
78=2[(x+4)+(2x+2)]
78=2(3x+6)
78=6x+12
78-12=6x
66=6x
X=66/6
X=11
78=2[(x+4)+(2x+2)]
78=2(3x+6)
78=6x+12
78-12=6x
66=6x
X=66/6
X=11
Answered by
0
Answer:
Length = 15 m
Breadth = 24m
Step-by-step explanation:
Given,
Length ( L ) = x + 4
Breadth ( B ) = 2x + 2
Perimeter of Rectangle = 2(L + B) = 78 m
Now,
Since Perimeter
= 2(L + B) = 78
=> 2(x + 4 + 2x +2) = 78
=> 2(3x + 6) = 78
=> 2 × 3(x + 2) = 78
=> 6(x + 2) = 78
=> x + 2 = 78/6
=> x + 2 = 13
=> x = 13 - 2
=> x = 11
Since x = 11
Length ( L ) = x + 4 = 11 + 4 = 15 m
Breadth ( B ) = 2x + 2 = 2(11) + 2 = 22 + 2 = 24 m
Hope it helps
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