Question

Find the lengths of the sides of the triangle whose vertices are A(3,4),B(2,-1) and C(4,-6).​

Answer 1

Answer:

Distance between two points (x1, y1) and (x2,y2) is = √{(x2-x1)²+(y2-y1)²}

Apply the formula.

Then you get,

AB = √5²+5² = 5√2 units

BC = √2²+5² = √29 units

CA = √1²+10² = √101 units