Question

find the lenth of rectangle whose perimeter 330cm and breadth is 45 cm?​

Answer 1

Step-by-step explanation:

perimeter of the rectangle=330cm

lenght =Xcm

breadth=45cm

perimeter= 2(l+b)

330=2(x+45)

165=x+45

x=165-45

x=125cm

length of the rectangle =125cm

Answer 2

perimeter of rectangle is 2( l + b ).

b = 45 cm

perimeter = 330 cm

putting the value in the formula we get:-

330 = 2( l + 45 )

330 = 2l + 90

2l = 330 - 90

( Subtracting 90 from both sides)

2l = 240

$l = \frac{240}{2}$

dividing 2 from both sides.

$l = 120$

Hence the length of the rectangle is 120 cm

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