Question

Find the lenth of the perpendicular from the point (3,-2) to the straight line 12x-5y+6=0:

Answer 1

$\textbf{Answer :}$

The given line is

12x - 5y + 6 = 0 ...(i)

So, the perpendicular distance of the line (i) from the point (3, - 2) be

= {(12 × 3) - 5 × (- 2) + 6}/√{12² + (- 5)²} units

= (36 + 10 + 6)/√(144 + 25) units

= 52/√169 units

= 52/13 units

= 4 units

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