find the lest 5 digit no..which on dividing by 6,9,12and 18 leaves a remaimder 3 in each case
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The lowest common multiple of 6, 9, 12 and 18 is 36.
So the result will be of the form 36k + 3, where k is an integer.
You want the first number of this form that is greater than 9999
36k + 3 > 9999
36k > 9996
k > 9996/36
k > 277 2/3
Round up to the next integer:
k = 278
Multiply that by 36 and add 3.
36 * 278 + 3
= 10011
Double-check:
10011 / 6 = 1668 r 3
10011 / 9 = 1112 r 3
10011 / 12 = 834 r 3
10011 / 18 = 556 r 3
Answer:
10,011
Hope it helps
So the result will be of the form 36k + 3, where k is an integer.
You want the first number of this form that is greater than 9999
36k + 3 > 9999
36k > 9996
k > 9996/36
k > 277 2/3
Round up to the next integer:
k = 278
Multiply that by 36 and add 3.
36 * 278 + 3
= 10011
Double-check:
10011 / 6 = 1668 r 3
10011 / 9 = 1112 r 3
10011 / 12 = 834 r 3
10011 / 18 = 556 r 3
Answer:
10,011
Hope it helps
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