find the lest no by which must be subtracted 3250 to make a perfect square
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This demonstrates (85)2 is under 7250 by 25
So, minimal number to be subtracted from 7250 is 25 Required flawless square no =7250−25 =7225
Answer: 25
When u subtract 1 from 3250 then it ends up idealize square of 57.
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