Question

Find the letterd angle in fig. ii

Answer 1

angle adb =90
x +90+60=180
x=30
y+40+90=180
y+130=180
y=50
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Answer 2

As the triangle ADC is a right angled triangle so the angle D Is 90°

AS WE THE SUM OF INTERIOR ANGLE OF A ∆ IS 180°,

SO ANGLE ACD=180=40°+90°+y
180°=130°+y

y=50°

AND THE ∆ ADB IS ALSO A RIGHT ANGLED ∆ SO THE ADB IS 90°

NOW,

180=60+90+x

180=150+x
x= 30°