Question

find the lettered angle
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Answer 1

Given:

<QPR = 59°

<RPS = 32°

To find:

x and y

solution:

In ∆PQR:

PR = QR

<QPR = <PQR = 59°

sum of all angles of a ∆ = 180°

59° + 59° + x° = 180°

118° + x° = 180°

x° = 180°- 118°

x° = 62°

In ∆PRS:

x is the exterior angle

<SPR + y = x

32° + y = 62°

y = 62° - 32°

y = 30°

Answer 2

Answer:

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