find the lettered angle
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X is 63 degrees because the triangles are congruent
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Answer:
x = 63°
Step-by-step explanation:
In Δ ADE, AE = AD
( we know angle opposite to equal sides are equal )
∴ ∠AED = ∠ADE
∴ ∠ADE = 63°
In Δ ADE,
∠A + ∠D + ∠E = 180° (angle sum property)
∠A + 63° + 63° = 180°
∠A + 126° = 180°
∴ ∠A = 54°
But ∠DAE = ∠CAB (vertically opposite angles)
∴ ∠CAB = 54°
In ΔABC, AB = AC
(we know angles opposite to equal sides are equal)
∴ ∠ACB = ∠ABC = x
In Δ ABC
∠A + ∠B + ∠C = 180° (angle sum property)
54° + x + x = 180°
2x = 126
x = 63°
hope it helps...
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