find the lettered angle in each case
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Hi friend
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Your answer
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Here,
In ∆ABC,
Angle ACB = 180° - (Angle BAC + Angle ABC)
=> Angle ACB = 180° - (50° + 90°)
=> Angle ACB = 180° - 140° = 40°
Again,
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In ∆DEC ,
X = 180° - (Angle DEC + Angle ACB)
=> X = 180° - (100° + 40°)
=> X = 180° - 140° = 40°
HOPE IT HELPS
---------------
Your answer
---------------------
Here,
In ∆ABC,
Angle ACB = 180° - (Angle BAC + Angle ABC)
=> Angle ACB = 180° - (50° + 90°)
=> Angle ACB = 180° - 140° = 40°
Again,
------------
In ∆DEC ,
X = 180° - (Angle DEC + Angle ACB)
=> X = 180° - (100° + 40°)
=> X = 180° - 140° = 40°
HOPE IT HELPS
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