Find the lettered angle in each case.
Answer is : x=40
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In ∆ABC,
∠A + ∠B + ∠C = 180° (Angle sum property of ∆)
50° + 90° + ∠C = 180°
∠C = 180° - 140°
∠C = 40°
In ∆DEC,
∠D + ∠E + ∠C = 180° (Angle sum property of ∆)
x + 100° + 40° = 180°
x = 180° - 140°
x = 40°
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