Question

Find the lettered angle in the figure​

Answer 1

Answer:

ABCD is a parallelogram so ,

AC = BD and CD = BA

[ since it's a parallelogram so as we know opposite sides are always equal to eachother]

in ∆ADC and ∆ABD

AD = DA ( common )

AC = BD ( given )

AC = BD ( given )

∆ADC and ∆ABD are congruent with SSS

so angle ACD = angle ABD by cpct

therefore angle ABD = 65°

[ cpct = congruent part of congruent triangle ]

hope this will help you~~