find the lettered angles
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❥ As we know,
∆ ABD = 180°
D = 90°
B = 60°
BAD = X
❥ ∆ ABD = BAD + ADB + DBA
180° = X + 90° + 60°
180° = X + 150°
180° - 150° = X
30° = X
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❥ As we know,
∆ ADC = 180°
D = 90°
C = Y
DAC = 40°
❥ ∆ ADC = DAC + ACD + ADC
180° = 40° + Y + 90°
180° = 130° + Y
180° - 130° = Y
50° = Y
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I hope it helps you
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