Find the lettered angles in each case :
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Answered by
6
Here,
Angle x = Angle FAE (vertically opposite angle)
Angle x = 70°
Angle z = 180°- AngleACD (Linear pair)
Angle z = 180° - 110°
Angle z = 70°
Now ,
In ∆ABC ,
x + y + z = 180°(sum of angles of a triangle is 180°)
70° + y + 70° = 180°
140° + y = 180°
y = 180° - 140°
y = 40°
So finally ,
x = 70°
y = 40°
z = 70°.....
Angle x = Angle FAE (vertically opposite angle)
Angle x = 70°
Angle z = 180°- AngleACD (Linear pair)
Angle z = 180° - 110°
Angle z = 70°
Now ,
In ∆ABC ,
x + y + z = 180°(sum of angles of a triangle is 180°)
70° + y + 70° = 180°
140° + y = 180°
y = 180° - 140°
y = 40°
So finally ,
x = 70°
y = 40°
z = 70°.....
ayush6260:
thanks
Answered by
7
x = 70° (Vertical Opposite Angle)
z = 180° - angle FCD ( linear pair)
z = 180° - 110°
z = 70°
angle x + angle y + angle z = 180° ( Angle sum property of a triangle)
=> 70° + y + 70° = 180°
=> 140° + y = 180°
=> y = 180° - 140°
=> y = 40°
x = 70°
y = 40°
z = 70°
HOPE IT HELPS YOU....
z = 180° - angle FCD ( linear pair)
z = 180° - 110°
z = 70°
angle x + angle y + angle z = 180° ( Angle sum property of a triangle)
=> 70° + y + 70° = 180°
=> 140° + y = 180°
=> y = 180° - 140°
=> y = 40°
x = 70°
y = 40°
z = 70°
HOPE IT HELPS YOU....
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