Question

Find the limit of (n^2+3n+5)/(6n^2+89n+1) as n tends to infinity​

Answer 1

Answer:

Answer

Correct option is

C

1/3

Solution

x→∞

lim

n

3

1

2

+2

2

+−−−n

2

we know that 1

2

+2

2

+−−−n

2

=

6

n(n+1)(2n+1)

=

x→∞

lim

6n

3

n(n+1)(2n+1)

=

x→∞

lim

6n

2

(n+1)(2n+1)

=

x→∞

lim

6n

2

2n

2

+3n+1

Apply L-Hospital rule twice.

=

x→∞

lim

12n

4n+3

=

12

4

=

3

1

Mark me as brain list