Question

Find the limit of the function f(x,y)= x+y-6 at x=1;y=2​

Answer 1

Answer:

0

Step-by-step explanation:

Let f(x,y)=xy3x2+y6 if (x,y)≠(0,0) and f(0,0)=0. Is this function continuous at (x,y)=(0,0)?

I believe that it is, because the function appears to be approaching 0 as (x,y)→(0,0), and the hole is filled there, but I'm not sure how to prove that the limit is 0.

Answer 2

Answer:

-3

Step-by-step explanation:

To find the limit, we just need to substitute the given numbers in the function and if the result is not an indefinite number, then it is the limit

So, Substituting, x=1;y=2 in f(x,y)= x+y-6

=> 1 + 2 - 6

=> 3 - 6

=> -3

This is the limit

Hope it helps!!