Question

Find the limit of x√x²+1/x+1 when tends to 1

Answer 1

Answer:

ans. 3

Step-by-step explanation:

$x \sqrt{ {x}^{2} } + \frac{1}{x } + 1 \\ = > \: x(x) + \frac{1}{x} + 1 \\ = > \: {x}^{2} + \frac{1}{x} + 1 \\ = > \: \: {1}^{2} + \frac{1}{1} + 1 \\ = > \: \: 1 + 1 + 1 = 3$