Question

find the limit (x^3-27)/x^2-9 Lt x is 3

Answer 1

divide by x-3 ...numerator as well as denominator ...
So required answer will be 3/2..

Answer 2

let , y = (x^3-27)/(x^2-9)

so y = (x-3)(x^2 +9 +3x)/(x-3)(x+3)

cancel out (x-3) from numerator and denominator,

=) y = (x^2 +3x +9)/(x+3)

now , lim y = (9 +9 +9)/(3+3) = 27/6 = 9/2

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hope it will help u