Math, asked by fj5fjd5kf66dkd7kdfl, 10 months ago

Find the limits:
lim​

Attachments:

Answers

Answered by ritu16829
0

Answer:

hey mate ❤️❤️

plz refer to pic

hope it works ❤️❤️

plz mark it as brainliest answer

Attachments:
Answered by CharmingPrince
10

\huge{ \green{ \mathfrak{ \underline{Questiom}}}}

▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂

■☆Find\; :\; \red{\displaystyle {\lim_{x \to 2} \left[ {\frac{x^2-4}{x^3-4x^2+4x}} \right] }}☆■

▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂

\huge{ \green{ \mathfrak{ \underline{Answer}}}}

▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂

\implies \blue{ \displaystyle{\lim_{x \to 2} \left[ {\frac{x^2-4}{x^3-4x^2+4x}} \right] }}

\implies \displaystyle{\lim_{x \to 2} \left[ {\frac{(x)^2 - 2^2}{x^3 - 4x^2 +4x}}\right] }

\implies \displaystyle{\lim_{x \to 2} \left[ {\frac{(x+2)(x-2)}{x(x-2)^2}} \right] }

\implies \displaystyle{\lim_{x \to 2} \left[ {\frac{(x+2)(x-2)}{x(x-2)(x-2)}} \right] }

\implies \displaystyle{\lim_{x \to 2} \left[ {\frac{x+2}{x(x-2)}} \right] }

\implies \purple{\left[ \displaystyle{\frac{2+2}{2(2-2)}} \right]}

\implies \green{\displaystyle{\frac{4}{0}} ,\: which \: is\: undefined}

▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂

Similar questions