find the linear equation 3x2-53x+232 =0
Answers
Answered by
5
3x^2-53x+232=0
3x^2-24x-29x+232=0
3x(x-8)-29(x-8)=0
(3x-29)(x-8)=0
x=29/3 or x=8
3x^2-24x-29x+232=0
3x(x-8)-29(x-8)=0
(3x-29)(x-8)=0
x=29/3 or x=8
Anonymous:
please can you mark me as brainliest
Answered by
1
Answer:
see photo for solution
cheese
:)
Attachments:
Similar questions