Question

find the linear equation such that its graph intersects x-axis at (-2,0) and the y-axis at (0,5)


hint : _ x + _ y + 20 = 0

Answer 1

equation of a straight line which intersects x axis at  (a, 0) and  y axis at (0, b) is given by

     x / a + y / b = 1

Hence,  x / -2  + y / 5 = 1
       =>  -5 x + 2 y = 10
     =>  - 5 x + 2y - 10 = 0

     =>  10 x - 4 y + 20 = 0

Answer 2

X intercept = -2
Y intercept = 5

The intercept form of a line is 

$\frac{x}{a} + \frac{y}{b} = 1$

$\frac{x}{-2} + \frac{y}{5} = 1$

5x - 2y = -10

5x - 2y + 10 = 0

As per your hint, 

10x - 4y + 20 = 0