Question

find the lines parallel to the line 9x+16y-127=0 passing through (4,5)​

Answer 1

Answer:

line is 9x+16y-116=0

Step-by-step explanation:

let line be 9x+16y+d=0

then satisfying by (4,5)

  36+80+d=0

d=  -116

Answer 2

Answer:

9x+16y-127= -11

Step-by-step explanation:

Let the equation of a plane parallel to the given plane be:

9x + 16y - 127=k....[1]

This passes through [4,5] so.

9*4+16*5-127=k

k = -11

Substituting this in (1), we get

9x+16y-127= -11

which is the equation of the required plane.