find the local maxima and minima
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on differentiating,
f'(x) = 4x^3 -124x + 120
equate to zero
4x^3 - 124x + 120 = 0
÷ by 4
x^3 - 31x + 30 = 0
on solving,
x = 5, 1, -6
f"(x) = 12x^2 - 124
f"(5) = 176....+ve,. f(x) has a min value here.
f"(1) = -112... -ve.. f(x) has max value here.
f"(-6)= 308... +ve...f(x) has again a min value here.
local minima,
f(5) = -316 and f(-6) = -207
local maximum,
f(1) = 68
hoping dis will be ri8...if ti is so pls mark it as brainliest
f'(x) = 4x^3 -124x + 120
equate to zero
4x^3 - 124x + 120 = 0
÷ by 4
x^3 - 31x + 30 = 0
on solving,
x = 5, 1, -6
f"(x) = 12x^2 - 124
f"(5) = 176....+ve,. f(x) has a min value here.
f"(1) = -112... -ve.. f(x) has max value here.
f"(-6)= 308... +ve...f(x) has again a min value here.
local minima,
f(5) = -316 and f(-6) = -207
local maximum,
f(1) = 68
hoping dis will be ri8...if ti is so pls mark it as brainliest
dragomegaman:
local minina is -1647 at x = -6.
local maxima is correct.
please provide me with correct minina if you can :)
hare follow the same step and find out correct ans
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