Question

find the locus of a point equidistant from the lines x+y+4=0
and 7x +y +20 =0

Answer 1

Please find the solved answer for this.  I’m also giving you a part of the solution

Squaring we get,

25(h+k+7)² = (7h+k+20)²

25h²+25k²+1225+50hk+350k+350h=49h²+k²+400+14hk+40k+280h

=24h²-24k²-825-36hk-310k-70h = 0

=putting x=h, k=y we get,

=24x² - 24y² - 36xy – 70x – 310y – 825 = 0

= This is an equation of hyperbola

Answer 2

answer y nahi h

x-2y=0, 6x+3y+20=0