Question

find the locus of a point equidistant from the point (2 4) and the y-axis

Answer 1

We have to given that a point is in equidistant from point(2,4) and y-axis.

So let the point is (x,y)

so distance of this point from (2,4) and y-axis is same.

√((x-2)^2+(y-4)^2)=x

((x-2)^2+(y-4)^2)^2=x^2

(y-4)^2=x^2-(x-2)^2

(y-4)^2=4x-4

(y-4)^2=4(x-1)

That is a locus of (x,y) is parabola.