Question

Find the locus of a point equidistant from the three vertices and
sides of a triangle.​

Answer 1

Answer:

Step-by-step explanation:

The locus of point ℓ equidistant from three vertices is the circumcentre and three sides of a triangle is the incentre of the triangle.

Here, J is the incentre of the ∆LMN.

At first draw the angle bisectors of all the angles i.e, ∠L , ∠M and ∠N.

LO, MP and NQ are the angle bisectors respectively.

Let LO, MP and NQ intersect at J,

∴ J is the incentre.

Here, U is the circumcenter of the ∆RST.

At first , draw the perpendicular bisectors of the sides ST, RT and RS of the triangle.

Here, RC, SB and AT are the required perpendicular bisectors.

Lat them intersect at U

Hence, U is the circumcenter of the triangle.

Answer 2

Answer:

Hi

Step-by-step explanation:

The locus of point ℓ equidistant from three vertices is the circumcentre and three sides of a triangle is the incentre of the triangle.

Here, J is the incentre of the ∆LMN.

At first draw the angle bisectors of all the angles i.e, ∠L , ∠M and ∠N.

LO, MP and NQ are the angle bisectors respectively.

Let LO, MP and NQ intersect at J,

∴ J is the incentre.

Here, U is the circumcenter of the ∆RST.

At first , draw the perpendicular bisectors of the sides ST, RT and RS of the triangle.

Here, RC, SB and AT are the required perpendicular bisectors.

Lat them intersect at U

Hence, U is the circumcenter of the triangle.