Question

Find the locus of a point, the difference of whose distances from (-5,0) and (5,0)
is 8.
​

Answer 1

Answer:

Let the point be (x,y),

 By using distance formula for coordinates,

[(x+5)2+(y−0)2]21−[(x−5)2+(y−0)2]21=8

⇒[x2+10x+25+y2]21=[x2−10x+25+y2]21+8

 squaring on both sides,

⇒x2+10x+25+y2=x2−10x+25+y2+64+16[x2−10x+25+y2]21

⇒5x−16=4[x2−10x+25+y2]21

Again squaring  both sides,

⇒25x

Step-by-step explanation:

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