Find the locus of a point, the difference of whose distances from (-5,0) and (5,0)
is 8.
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Answer:
Let the point be (x,y),
By using distance formula for coordinates,
[(x+5)2+(y−0)2]21−[(x−5)2+(y−0)2]21=8
⇒[x2+10x+25+y2]21=[x2−10x+25+y2]21+8
squaring on both sides,
⇒x2+10x+25+y2=x2−10x+25+y2+64+16[x2−10x+25+y2]21
⇒5x−16=4[x2−10x+25+y2]21
Again squaring both sides,
⇒25x
Step-by-step explanation:
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