Question

find the locus of a point which moves such that its distance form (-4,3) is 5​

Answer 1

Answer:

${x}^{2} + {y}^{2} + 8x - 6x = 0$

Step-by-step explanation:

$\sqrt{ {(x + 4)}^{2} + {(y - 3)}^{2} } = 5 \\ \\ {(x + 4)}^{2} + {(y - 3)}^{2} = 25 \\ \\ {x}^{2} + {y}^{2} + 8x - 6x + 25 = 25 \\ \\ {x}^{2} + {y}^{2} + 8x - 6x = 0$

Answer 2

Answer:

Answer:

x2+y2+8x−6x=0{x}^{2} + {y}^{2} + 8x - 6x = 0x

2

+y

2

+8x−6x=0

(x+4)

2

+(y−3)

2

=5

(x+4)

2

+(y−3)

2

=25

x

2

+y

2

+8x−6x+25=25

x

2

+y

2

+8x−6x=0