Question

find the locus of ex-centre of right triangles with given hypotenuse.​

Answer 1

hi frnd

ANSWER

Let P(x,y) be the point.

slope of 1st side =(y−4)/x.

slope of 2ndsidey/(x−4).

By this property,

y(y−4)/x(x−4)=−1.

y2−4y=4x−x2

x2+y2−4x−4y=0 is a locus of required points.

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