Find the locus of the mid point of x and y-intercepts of a variable straight line touching ellipse x^2/a^2 + y^2/b^2 = 1
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Answer:
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Step-by-step explanation:
Let mid-point of part PQ which is in between the axis is R(x
1
,y
1
), then coordinates of P and Q will be (2x
1
,0) and (0,2y
1
), respectively.
∴ Equation of line PQ is
2x
1
x
+
2y
1
y
=1
⇒y=−(
x
1
y
1
)x+2y
1
If this line touches the ellipse
x
2
a
2
+
y
2
b
2
=1
then it will satisfy the condition,
c
2
=a
2
m
2
+b
2
So, (2y
1
)
2
=a
2
(
x
1
−y
1
)
2
+b
2
⇒4y
1
2
={
x
1
2
a
2
y
1
2
}+b
2
⇒4=(
x
1
2
a
2
)+(
y
1
2
b
2
)⇒(
x
1
2
a
2
)+(
y
1
2
b
2
)=4
∴ Required locus of (x
1
,y
1
) is
x
2
a
2
+
y
2
b
2
=4
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