Find the locus of the point x = a +bseco, y = b + a tano.
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1
Answer:
Step-by-step explanation:
Given,
x
=
a
+
b
sec
θ
x
−
a
b
=
sec
θ
...(i)
Also given,
y
=
b
+
a
tan
θ
⇒
y
−
b
a
=
tan
θ
...(ii)
Now we know that
sec
2
θ
−
tan
2
θ
=
1
⇒
(
x
−
a
b
)
2
−
(
y
−
b
a
)
2
=
1
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