find the locus of the points which is
equidistant from the coordinate axes
Answers
Step-by-step explanation:
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The point which is equidistant from the coordinate axes are , (x,y) and (-x,y), (-x, -y) and (x, -y).
We have to find that curve which passes through all these four points.
Distance from x axis to each of these point = x
Distance from y axis to each of these point = y
Distance from Origin to any of these point
Squaring both sides
x² +y²=r²
Which is a Circle.
So,equation of locus is a circle .
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