Question

Find the locus of the third vertex of a right angled triangle, the ends of whose
hypotenuse are (4.0) and (0,4).​

Answer 1

Step-by-step explanation:

7

Diride 184 into

two parts such that 1/3 of

I part may exceed

1/7th of

another part by

8

7

Diride 184 into

two parts such that 1/3 of

I part may exceed7

Diride 184 into

two parts such that 1/3 of

I part may exceed

1/7th of

another part by

87

Diride 184 into

two parts such that 1/3 of

I part may exceed

1/7th of

another part by7

Diride 184 into

two parts such that 1/3 of

I part may exceed

1/7th of

another part by7

Diride 184 into

two parts such that 1/3 of

I part may exceed

1/7th of

another part by

87

Diride 184 into

two parts such that 1/3 of

I part may exceed

1/7th of

another part by

8

8

8

1/7th of

another part by

8

7

Diride 184 into

two parts such that 1/3 of

I part may exceed

1/7th of

another part by

8

7

Diride 184 into

two parts such that 1/3 of

I part may exceed7

Diride 184 into

two parts such that 1/3 of

I part may exceed

1/7th of

another part by

87

Diride 184 into

two parts such that 1/3 of

I part may exceed

1/7th of

another part by7

Diride 184 into

two parts such that 1/3 of

I part may exceed

1/7th of

another part by7

Diride 184 into

two parts such that 1/3 of

I part may exceed

1/7th of

another part by

87

Diride 184 into

two parts such that 1/3 of

I part may exceed

1/7th of

another part by

8

8

8

1/7th of

another part by

8

7

Diride 184 into

two parts such that 1/3 of

I part may exceed

1/7th of

another part by

8

7

Diride 184 into

two parts such that 1/3 of

I part may exceed7

Diride 184 into

two parts such that 1/3 of

I part may exceed

1/7th of

another part by

87

Diride 184 into

two parts such that 1/3 of

I part may exceed

1/7th of

another part by7

Diride 184 into

two parts such that 1/3 of

I part may exceed

1/7th of

another part by7

Diride 184 into

two parts such that 1/3 of

I part may exceed

1/7th of

another part by

87

Diride 184 into

two parts such that 1/3 of

I part may exceed

1/7th of

another part by

8

8

8

1/7th of

another part by

7

Diride 184 into

two parts such that 1/3 of

I part may exceed

1/7th of

another part by

8

7

Diride 184 into

two parts such that 1/3 of

I part may exceed7

Diride 184 into

two parts such that 1/3 of

I part may exceed

1/7th of

another part by

87

Diride 184 into

two parts such that 1/3 of

I part may exceed

1/7th of

another part by7

Diride 184 into

two parts such that 1/3 of

I part may exceed

1/7th of

another part by7

Diride 184 into

two parts such that 1/3 of

I part may exceed

1/7th of

another part by

87

Diride 184 into

two parts such that 1/3 of

I part may exceed

1/7th of

another part by

8

8

8

1/7th of

7

Diride 184 into

two parts such that 1/3 of

I part may exceed

1/7th of

another part by

8

7

Diride 184 into

two parts such that 1/3 of

I part may exceed7

Diride 184 into

two parts such that 1/3 of

I part may exceed

1/7th of

another part by

87

Diride 184 into

two parts such that 1/3 of

I part may exceed

1/7th of

another part by7

Diride 184 into

two parts such that 1/3 of

I part may exceed

1/7th of

another part by7

Diride 184 into

two parts such that 1/3 of

I part may exceed

1/7th of

another part by

87

Diride 184 into

two parts such that 1/3 of

I part may exceed

1/7th of

another part by

8

8

8

1/7th of

another part by

8

another part by

8

8

Answer 2

Answer:

0,0 is locus of the third vertex.

Step-by-step explanation:

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