Find the locus of z if it is given.
|z-2|
------------ = 1
|z-3|
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Answer:
Given ∣z−2−3i∣=1
Put z=x+iy
⇒∣(x−2)+i(y−3)∣=1
Modulus of (x−2)+i(y−3) is
(x−2)
2
+(y−3)
2
⇒
(x−2)
2
+(y−3)
2
=1
⇒(x−2)
2
+(y−3)
2
=1
Hence, the locus is a circle in complex plane with centre (2,3)and radius 1 unit
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