Question

Find the locus on a point which is equidistant from 2,0 and you axis

Answer 1

Answer:

Answer

Step-by-step explanation:

Let the point be P(h,k)

Given,

P is equidistant from A(2,0) and the Y axis

⇒

(h−2)

2

+K

2

=h

⇒(h−2)

2

+K

2

=h

2

[Squaring]

⇒h

2

+4−4h+K

2

=h

2

⇒K

2

=4(h−1)

Replacing (h.k) with (x,y) we get

y

2

=4(x−1)