find the log ( 2.47 × 10^-29),
full method
Answers
Answer:
In case 2, e, or 10 is the base you wanted, I have calculated these for you:
In case 2, e, or 10 is the base you wanted, I have calculated these for you:base 2: ln 2 = 0.6931…, so lb 2.47 = 1.305.
In case 2, e, or 10 is the base you wanted, I have calculated these for you:base 2: ln 2 = 0.6931…, so lb 2.47 = 1.305.base e: ln e = 1 (exactly by definition), so ln 2.47 = 0.904.
In case 2, e, or 10 is the base you wanted, I have calculated these for you:base 2: ln 2 = 0.6931…, so lb 2.47 = 1.305.base e: ln e = 1 (exactly by definition), so ln 2.47 = 0.904.base 10: ln 10 = 2.303…, so lg 2.47 = 0.393.
In case 2, e, or 10 is the base you wanted, I have calculated these for you:base 2: ln 2 = 0.6931…, so lb 2.47 = 1.305.base e: ln e = 1 (exactly by definition), so ln 2.47 = 0.904.base 10: ln 10 = 2.303…, so lg 2.47 = 0.393.In case anyone wishes to object to my “pedantic” answer because they always use log to mean base ___ (fill in the blank) and “everybody” knows that, I can fairly well tell what your career orientation is:
In case 2, e, or 10 is the base you wanted, I have calculated these for you:base 2: ln 2 = 0.6931…, so lb 2.47 = 1.305.base e: ln e = 1 (exactly by definition), so ln 2.47 = 0.904.base 10: ln 10 = 2.303…, so lg 2.47 = 0.393.In case anyone wishes to object to my “pedantic” answer because they always use log to mean base ___ (fill in the blank) and “everybody” knows that, I can fairly well tell what your career orientation is:Mathematicians and physicists assume e.
In case 2, e, or 10 is the base you wanted, I have calculated these for you:base 2: ln 2 = 0.6931…, so lb 2.47 = 1.305.base e: ln e = 1 (exactly by definition), so ln 2.47 = 0.904.base 10: ln 10 = 2.303…, so lg 2.47 = 0.393.In case anyone wishes to object to my “pedantic” answer because they always use log to mean base ___ (fill in the blank) and “everybody” knows that, I can fairly well tell what your career orientation is:Mathematicians and physicists assume e.Engineers assume 10.
In case 2, e, or 10 is the base you wanted, I have calculated these for you:base 2: ln 2 = 0.6931…, so lb 2.47 = 1.305.base e: ln e = 1 (exactly by definition), so ln 2.47 = 0.904.base 10: ln 10 = 2.303…, so lg 2.47 = 0.393.In case anyone wishes to object to my “pedantic” answer because they always use log to mean base ___ (fill in the blank) and “everybody” knows that, I can fairly well tell what your career orientation is:Mathematicians and physicists assume e.Engineers assume 10.Computer scientists assume 2.
Step-by-step explanation:
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