Question

find the log 32to the base 2

Answer 1

Answer:

Step-by-step explanation:

To determine the value of log_(2)32

we use the meaning of logarithms:log_(a)b = x rArr a^x = b

Therefore we let log_(2)32 = x

We rewrite as 2^x = 32

Next, we'll rewrite 32 as a power of 2.  32 = 2^5

2^x = 2^5

Therefore x = 5 as we have the same base

Answer 2

HERE IS YOUR ANSWER MATE :

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$log_{2}(32) \\ = log_{2}( {2}^{5} ) \\ = 5 log_{2}(2) \\ = 5 \times 1 \\ = 5$

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