find the log
log1/3^(81)
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Answered by
6
Answer:
Rewrite as an equation.
log1/3(81)=x in exponential form using the definition of a logarithm. If x and b are positive real numbers and bdoes not equal.
1, then log b(x)=y is equivalent to by=x.
.(1/3)x=81
Create expressions in the equation that all have equal bases.
(3−1)x=34
=34
Rewrite
(3−1)x as 3−x.
3-x=34
Since the bases are the same, then two expressions are only equal if the exponents are also equal.
−x=4
Solve for x.
x=−4
The variable x is equal to −4.
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Answered by
2
Answer:
log 1/3^ 81
===> ( 81 )^x = 1/3
===> ( 3^4)^x = 3^1
[ ( a^m ) ^ n = a ^ m + n ]
===> 3^4x = 3^1
Here , if the bases are equal then their exponents are also equal
4x = 1
x = 1/4
log^3 to the base of 81 = 1/4
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