Question

find the logorithms of 1728 to base 2 root 3​

Answer 1

Answer:

$log_{ \sqrt[3]{2} }(1728) = > log_{ {2}^{ \frac{1}{3}}}(27 \times 64) = >$

$log_{ {2}^{ \frac{1}{3} }}(27) + log_{ {2}^{ \frac{1}{3}}}(64) = > log_{ {2}^{ \frac{1}{3} } }( {3}^{3} )$

$+ log_{ {2}^{ \frac{1}{3}} }( {2}^{6} ) = > log_{ {2}^{ \frac{1}{3}} }( {3}^{9} ) ^{ \frac{1}{3} } + 18 = >$

$= > 9 \frac{ log(3) }{ log(2) } + 18 = > 9 \times \frac{0.477}{0.301} + 18$

$= > 18 + 14.2646625 = > 32.2646625$

Hope it helps you.