Question

find the longest altitude of the triangle whose sides are 35 cm, 54 cm and 61 cm.​

Answer 1

Step-by-step explanation:

s=2a+b+c=235+54+61=75

Area, A=s(s−a)(s−b)(s−c)=75(75−35)(75−54)(75−61)=4205cm2 

Now, Area of the triangle is also given as A=21×a×h

Where, h is the longest altitude.

Therefore, 21×a×h=4205

Hence, h=245 cm

Answer 2

Answer:

245 cm

Step-by-step explanation:

s=2a+b+c=235+54+61=75

Area, A=s(s−a)(s−b)(s−c)=75(75−35)(75−54)(75−61)=4205cm2  

Now, Area of the triangle is also given as A=21×a×h

Where, h is the longest altitude.

Therefore, 21×a×h=4205

Hence, h=245 cm