Question

find the longest and shortest wavelength in the Lyman series' for hydrogen .in what region of the electromagnetic spectrum does series lie
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Answer 1

Answer:

sorry my maths is week I don't know

Answer 2

Answer:

Explanation:

The transition equation for Lyman series is given by

1λ=R(112−1n2). N = 2,3….Thelar≥stwave≤n>hiscorresponds→n = 2:. (1)/(lambda_(max)) = 1.097 xx 10^(7)) ((1)/(1) - (1)/(4))= 0.823 xx 10^(7)implies lambda_(max) = 1.2154 xx 10^(7) m = 1215 ÅTheshortestwave≤n>hcorresponds→n = oo:. (1)/(lambda_(min)) = 1.097 xx 10^(7)) ((1)/(1) - (1)/(oo))or lambda_(min) = 0.911 xx 10^(-7) m = 911 ÅBothofthesewave≤n>hlie∈thet–ravio≤t(UV)` region of electromagnetic spectrum. S