Question

Find the longest rod thatbcan put im box pf dimension 6*3*2

Answer 1

✨✨✨ Hey ✨✨✨

Your Answer : -

$diagonal \: = \sqrt{ {l}^{2} + {b \: }^{2} + {h}^{2} }$

Given

l = 6

b = 3

h= 2

on putting it into the formula,

we get

$d \: = \: \sqrt{36 + 9 + 4}$

$d \: = \: \sqrt{49} \\</em><em> </em><em>\</em><em>\</em><em> d = 7 \: units$

THE LONGEST ROD CAN BE PUT IT INTO BOX IS OF 7 UNITS

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