find the longest wavelength in paschen series
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wavelength denoted as lembda
so,
lambda maximum for pasvhen serues will be..
1/lembda= R{1/(3)^2-1/(4)^2}
1/lembda= R {1/9-1/16)}
1/lembda=1.0967 x 10^7 (1/9-1/16)
solve this to get the value of lembda
hope it will help u
# Phoenix
wavelength denoted as lembda
so,
lambda maximum for pasvhen serues will be..
1/lembda= R{1/(3)^2-1/(4)^2}
1/lembda= R {1/9-1/16)}
1/lembda=1.0967 x 10^7 (1/9-1/16)
solve this to get the value of lembda
hope it will help u
# Phoenix
akankaha18:
thank you
Answered by
5
I am sending a picture of my solution .
Kindly see it.
Hope my answer helps you.
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