Find the loss or gain as percent, if the c. p. Of 8 articles a, all of the same kind, is equal to s. p of 10 articles
Answers
AnswEr :
• Loss Percentage in the Case :
⠀
∴ Hence, Loss Percentage will be 20%.
Question :--- Find the loss or gain as percent, if the c. p. Of 8 articles a, all of the same kind, is equal to s. p of 10 articles ...
Solution (1) :--- Lets Try it with Basic Method First .
Let CP of one article = Rs. x
Than , CP of 8 article = Rs. 8x = SP of 10 article..
Now, Cp of 10 article = Rs. 10x
Now, we know that, when CP is more than SP , we have Loss . That is given by :--
Loss = CP - SP
→ Loss = CP of 10 article - SP of 10 article
Putting value of SP of 10 article from above we get :--
→ Loss = 10x - 8x
→ Loss = Rs. 2x
So, their was a loss of Rs.2x .
Now, Profit and Loss % is always on CP .
→ Loss % = (Loss in Rs.) * 100/ (CP)
Putting values we get ,
→ Loss % = (2x) * 100 / 10x [ As Loss was on 10 articles]
→ Loss % = 20% .
Hence, in this case , we have Loss of 20% ..
______________________________
Solution (2) :--- Lets try it with Ratio Method now,. .
Given :-
→ CP of 8 article = SP of 10 article
→ 8 CP = 10 SP
→ CP / SP = 10/8
→ CP / SP = 5/4
So, CP = 5 unit , SP = 4 unit .
→ Loss = CP - SP = 5 - 4 = 1 unit
→ Loss % = Loss * 100/ CP
→ Loss % = 1 * 100 / 5 = 20% .
Hence, their will be Loss of 20% in this case.
______________________________
Solution (3) :--- Lets See Direct Formula Now ,,,
→ If CP of A article = SP of B article
and , we have , A > B ,,
Than Their will be Always Gain .
And , in This case , Gain % is Given by = [ ( A-B)*100/B ]
→ and , if we have, A < B ,,
Than, Their will be Loss Always..
And , in This case , Loss % is Given by = [ (B-A)*100/B ]
so, From Question we have,
→ A = 8
→ B = 10
Since, A < B ,
it will be Loss in This case. ( As Discuss) .
Hence, Loss % = [ (10 - 8) * 100 / 10 ]
→ Loss % = 2* 100 / 10