Question

find the loucs of the point which is equidistant from (-1,1)and(4,-2)

Answer 1

2222222222222222222222222222222222222222222222

Answer 2

Answer:A(0, y)

B(5, 2)

C(-3, 2)

AP^2=AQ^2 (equidistant)

•(0-5) ^2 +[y-(-12)]=(0-(-3)) +(y-2)

•25+y^2+4y+4=9+y^2-4y+4

•4y+4y=9-25

•8y=-16

•|"y=-2"

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