Math, asked by roysudipta620, 3 months ago

Find the lowest common multipel of:- 12^2- 23xy+10y^2, 4x^2-9xy+5y^2, 3x^2-5xy+2y^2​

Answers

Answered by deepikasinghdangoriy
1

Answer:

=12x^2-23xy+10y^2

=12x^2-15xy-8xy+10y^2

=3x(4x-5y)-2y(4x-5y)

=(3x-2y)(4x-5y)---------->(1)

=4x^2-9xy+5y^2

=4x^2-4xy-5xy+5y^2

=4x(x-y)-5y(x-y)

=(4x-5y)(x-y)--------------->(2)

=3x^2-5xy+2y^2

=3x^2-3xy-2xy+2y^2

=3x(x-y)-2y(x-y)

=(3x-2y)(x-y)------------------(3)

L.C.M= (x-y) (3x-2y) (4x-5y)

i hope it is useful for you

Step-by-step explanation:

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