find the lowest natural no which when divided by 112,140 and 168 leaves a remainder 8 in each case ?
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Heya user! Here is your answer.
First of all, we will find the factors of 112, 140, 168
112 = 2 × 2 × 2 × 2 ×7
140 = 2 × 7 × 2 × 5
168 = 2 × 2 × 2 × 3 × 7
Common factors = 2 × 7 × 2
Uncommon factors = 2 × 2 × 5 × 2 × 3
Therefore, 2 × 2 × 7 × 2 × 2 × 5 × 2 × 3 = 3360
To find the lowest natural number with remainder 8
= 3360 + 8
=
First of all, we will find the factors of 112, 140, 168
112 = 2 × 2 × 2 × 2 ×7
140 = 2 × 7 × 2 × 5
168 = 2 × 2 × 2 × 3 × 7
Common factors = 2 × 7 × 2
Uncommon factors = 2 × 2 × 5 × 2 × 3
Therefore, 2 × 2 × 7 × 2 × 2 × 5 × 2 × 3 = 3360
To find the lowest natural number with remainder 8
= 3360 + 8
=
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