Find the lowest natural number which when divided by 112,140,168 leaves a remainder 8 in each case.
Answers
Answered by
12
112-8=104
140-8=132
168-8=160
Taking HCF
104=2*2*2*13
132=2*2*3*11
160=2*2*2*2*2*5
So HCF=2*2=4
4is the answer.
140-8=132
168-8=160
Taking HCF
104=2*2*2*13
132=2*2*3*11
160=2*2*2*2*2*5
So HCF=2*2=4
4is the answer.
Answered by
3
hi.........how r u.........
Similar questions