Question

Find the lowest natural number which when divided by 12, 15, 20 and 27 leaves remainder 6 in
each case​

Answer 1

Answer:

Given:

The required number is always left remainder as 4 when it is divided by 12, 15, 20 or 54

Concept Used:

Required number = LCM of divisors + Remainder

Calculation:

LCM of 12, 15, 20 and 54 is 540

Required number is 540 + 4 = 544

∴ Required least such number is 544.

Answer 2

Answer:

uyhuuuuuuuuuuh yub yuv is not possible in 6